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QUESTION 1 A bowling ball rolls 1.3 m up a ramp without slipping. It has an initial speed of its center of mass of 7.6 m ramp
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Answer #1

using conservation of energy

0.5 m v^2 = mgh + 0.5* mu^2 + 0.5 I w^2

0.5 m v^2 = mg h + 0.5 m u^2 + 0.5* ( 2 /5) m r^2 (u^2/r^2)

0.5* 7.6^2 = 9.8* 1.3 sin 28.8 + 0.7 u^2

v = 5.7 m/s

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