Question

The percent distribution of live multiple-delivery births (three or more babies) in a particular year for women 15 to 54 years old is shown in the pie chart. Find each probability. a. Randomly selecting a mother 30-39 years old P(30 to 39) b. Randomly selecting a mother not 30-39 years old P(not 30 to 39) c. Randomly selecting a mother less than 45 years old P(less than 45) d. Randomly selecting a mother at least 20 years old P(at least 20)

Answer 1

a) From the pie chart we see that there are 37.2% mothers in between age 30 - 34 and 24.6% in between 35 - 39

Hence the required probability is 0.372+0.246=0.618

That is 61.8%

b) Since P(not A) =1-P(A)

So the required probability is 1-0.618=0.382

That is 38.2%

c) Since there are only 3.7% mothers of age greater than 45,

So the required probability is

a) From the pie chart we see that there are 37.2% mothers in between age 30 - 34 and 24.6% in between 35 - 39 Hence the required probability is 0.372 + 0.246 = 0.618 That is 61.8% b) Since P(not A) = 1 - P(A) So the required probability is 1 - 0.618 = 0.382 That is 38.2% c) Since there are only 3.7% mothers of age greater than 45, So the required probability is 1 - 0.037 = 0.963 That is 96.3% d) As there are 1.3% mothers of age less than 20 So the required probability is 1 - 0.013 = 0.987 That is 98.7%

That is 96.3%

d) As there are 1.3% mothers of age less than 20

So the required probability is $1-0.013=0.987$

That is 98.7%