a) First, we will balance the reaction, by adding 1/2 to the coefficient of oxygen

Then we will find Entropy Change of the system
![ASsys = Sproducts – Spactants = ASys = Sco: - ($%, +sco) ASsys = [213.8 - (0.5 x 205.5 * 197.7)]J/mol. K AS y = -86.4J/mol K](http://img.homeworklib.com/questions/7153c0f0-1191-11ea-b0b6-eb44d5633783.png?x-oss-process=image/resize,w_560)
Thus, the answer will be -86.4 J/mol.K (Up to one decimal place)
b)
For the surrounding, we will assume ambient temperature of 298.15 K
Enthalpy of reaction = -566.0 kJ = -566.0 kJ x (1000 J/kJ) = -566 x 103 J
The entropy change will be,

Thus, the entropy change for surrounding will be 1898.4 J/K
c) Entropy of the universe will be,
![AS univ = ASsys + ASgurr = [(-86.4) + 1898.37]J/K = 1811.97J/K](http://img.homeworklib.com/questions/72184b20-1191-11ea-bb2d-cbc50fe57ac7.png?x-oss-process=image/resize,w_560)
Thus, the answer will be 1812.0 J/K
d)
We assume the temperature to be T. The reaction will be unfavourable when the total entropy of the universe becomes negative.
The total entropy will be given as

Thus, for reaction becoming non-spontaneous, we have,

Thus, the answer will be 6550.9 K
CO(g) + O2(g) -> CO2(g) (unbalanced) Using the equation and thermodynamic data: AH(rxn) --566.0 kJ (for the bal...
Using the equation and thermodynamic data: CO(g) + O2(g) --> CO2(g) (unbalanced) AH(rxn) = -566.0 kJ ( for the balanced equation) Substance sºu/mol*K) O2(g) 205.0 CO(g) 197.7 CO2(g) 213.8 NOTE: Write all answers to four significant figures. a. What is the Assys(J/mol*K) = b. What is the Assurr(J/mol*K) = c. What is the Asuniv( J/mol*K) = d. At what temperature(°C) will the reaction go from spontaneous to non-spontaneous?
7) 2 N2(g) + O2(g) → 2 N20(g) AH rxn = + 163.2 kJ a) At 25°C; calculate ASsurr = b) Is ASsys > 0 or < 0? Explain your answer c) Is the reaction spontaneous? AS univ = (ASsurr) + ( ASsys)
Which one of the following is FALSE? The following reaction 2 NO2(g) → 2 NO(g) + O2(g), Ahº, 1xn = +113.5 kJ, is not spontaneous at any temperature For the following reaction 2CO(g) + O2(g) → 2002(g) + 4 H2O(g), AH°rxn=-566 kJ, ASuniv is positive at low temperature but negative al high temperature Ο If ΔΗ. Orxn=-115 kJ and AsOrxn = +263 J/K, then ASuniv> 0 at all temperatures For the following reaction CO2(g) → C(s) + O2(g), AH, =...
Given the following reaction and thermodynamic data: A(g) - B(g AH = -42.3 kJ/mol; AS = -125.2 J/(mol*K) Is this reaction spontaneous or non-spontaneous? Select one: a. non-spontaneous. o b. spontaneous. c. more information is needed to determine.
llicients. (unbalanced] C2H6(8) + O2(8) — CO2(g) + H2O(g) V C2H6()] = -84.667 kJ/mol Ah (CO2()) = -393.5 kJ/mol AHCO2(aq)] =-412.9 kJ/mol 120(g) = -241.826 kJ/mol AHH,00=-285.840 kJ/mol kJ
Which one of the following is NOT true? If Ано, =-115 kJ and as rxn -- +263 J/K, then ASuniv> 0 at all temperatures rxn The following reaction 2 NO2(g) → 2 NO(g) + O2(g), Ahº, is not spontaneous at any temperature rxn = +113.5 kJ, The following reaction • 2 H2S(g) → S2(g) + 2 H2(g) Ahº, rxn = +169.8 kJ has a AS surrof - 570 J/K at 298 K For the following reaction 2CO(g) + O2(e) →...
10) pts) For the unbalanced equation: C6H6 (1) + O2(g) → CO2(g) + H20 (1) AH = - 6535 kJ. What is AH when 45.67 g of CO2 is produced? Cottotit O2(g) 02 (g) thout Solo 2 11) (12 pts) A scientist mixed 25.00 mL of 2.00 M KOH with 25.00 mL of 2.00 M HBr. The temperature of the mixed solution rose from 22.7 °C to 31.9°C. Assume that the volumes are additive, and the density of the solution...
6. Use the following thermodynamic data to calculate me following thermodynamic data to calculate AS for the formation of Fe2O3 at 298.2 K Species Fe(s) O2(g) Fe2O3(s) AH (kJ/mol-rxn) S (J/Komol-rxn) AH producers - 0.0 27.8 0.0 Alveolu 205.1 -825.5 87.4 -825.5 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) a) -2202.7J/ KX b) -546.2 J/K AS-A Sproducts-AS rearsants c) +546.2 J/K d) +2202.7J/ KV (2 X 87,4)-((4X27.8)+(3x205.1)) e) +4984.9 J/K 1 = 174,8-(111.27615.3) Ssurr -4H = 174,8-726.5 Assus =-551.75l...
Given the following Thermodynamic data: CO2(g) H2O(l) NH3(g) CO(NH2)2(s) DeltaHof (kJ/mol): -393.5 -285.85 -45.9 -333.2 So (J/K.mol): 214 70 193 105 (a) Calculate DeltaHo, DeltaSo, and DeltaGo at 25oC for the following reaction: CO2(g) + 2NH3(g) = CO(NH2)2(s) + H2O(l) (b) What is DeltaGo at 250oC? (Assume DeltaHo and DeltaSo do not change with temperature.) (c) Is the reaction spontaneous at each temperature? (Answer: (a) DeltaHo = -133.8 kJ; DeltaSo = -425 J/K; DeltaGo = -7.15 kJ; (b) DeltaGo =...
→ Fe(s) + CO2(g), AGº is - 5.8 kJ and AH° is -11 kJ. Sº (J mol-? K-'); 4. For the reaction Fe(s) + CO(g) Fe (27.3), CO(197.5), CO (213.7) a) What is AS sur? [37 JK-'] b) Use AG to determine whether the reaction is spontaneous or nonspontaneous under standard conditions. Explain. c) Use AS univ to determine whether the reaction is spontaneous or nonspontaneous under standard conditions. Explain. d) What is Sº for FeO? [61 J mol-'K-']