Question

Answer 1

Steps to be followed

1. Mass balance to prove F₀ = F as volume of reactor is constant

2. Component balance of C_A to get concentration profile, differential equation of C_A concentration contains Temperature term which is variable hence need temperature profile

3. Energy balance equation to get temperature profile but differential equation is dependent upon CA as heat of reaction will change over course of reaction

4. both differential equation are interlinked concentration profile and temperature profile is interlinked

To to go - CA е те е To, ko Sc Cpc exothermic by the reaction reacion in ESTR. heat released & transferred to way. -

0 concentration profile in CSIR = input - accumulation output a disappearance by in lum I CA VR - FO CAO - fca + (rm) v de (Co-w) - k.ee/et on it reactor volume is constant [fo=f] te volume of reaction - - - - 1 min. volumetric flow rate CAO - 2 komad / m² ko = 1010 /min R = 1.987 Keal/and K E = 13550 kead / kind = (- () - 1010 e 1927 * 7 CA 12550 689/1 E 2- 1010 e Coro Pet ( + 1010 da - 2-

Temperature profile ug up dr = rosu (to T) + -RG DHR VR - 2 (T-T) (p = 1.1 keal/kg k = 1000 kg/m3 Ve = m To =2936 1X1000 XH dar XIOPO XHI DT/ IXIDOD XH (523-T) + 12 X10 X 2X1 Roe E/RT CA DHE -2 (1-293 k) A1 + 13 x103 X2X1 Xloto e-s1957' CA = 323-T dk - 2 (T-23 1100 155/anta S T 35541 CA T = (323-T) + 23872 temp profa at - BIY (- 212)

Both of this differential equation is interdependent equation as temperature is dependent on Concentration while concentration is dependent on temperature

but for solving we need to take steady state and but dC_A/dt = 0 and dT/dt = 0

solution is regress and needs matlab as not possible to solve using calculator (it will exceed to 2 hours to write code and get graph)