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C according to the unbalanced equation below 75.5 g of solid CaO is reacted with 50.0 g 5) Determine the mass of the excess

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Answer #1

balanced equation is

2CaO + 5C ------------>2 CaC2 + CO2

75.5g/56g/mol 50g/12g/mol 0 0 intital moles

=1.348 =4.167

To know the limiting reagent , let us calculate the ratio of given to required moles

1.348/2= 0.674 4.167/5=0.833

Thus CaO is limiting reagent and C is excess reactant

Thus after reaction

2CaO + 5C ------------> 2 CaC2 + CO2

75.5g/56g/mol 50g/12g/mol 0 0 intital moles

=1.348 =4.167

0 4.167- ( 1.348x5/2)=2.482 1.348 0.674 after reaction

thus the excess reactant (carbn) remaining = 2.482 moles

mass remaining of Carbon = molesx molar mass= 2.482 mol x 12g/mol =29.784 g

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