Question

A 4 kg block moving to the right at 1 m/s over a frictionless surface strikes a 4 kg block moving to the left at 2 m/s. The collision is totally elastic. What is the final velocity (speed and direction) of each block?

Answer 1

Solo Givene mass of block, mi=m₂ =m=4kg initial velocity Vi= imls e elighwards) initial velocity V₂i = 42 m/s (left wards let Upf and Uzf be final uloity of blocks Sign inuention : Richowords=the respectivels 2 W, = imis twouds 3-ke!! Vi=-2 mis Condoration of momentum mit mi - myft mVzf 1-2 = 4ft Vzf lift Vzf = -)mls) 1. conservation of Freegy ☺ =) Vita a-(Vesti) Invi + tollze m vis + mvgs (1) ²+ (-2)² = (1,² (V2+)? .. -> (48)?+ (ver)= 5.:- from 6 20 [-(Ve+1)] + C24) ² = 5 Veget Vzf~4=0 if I mis , {"s=-2m/s/ Nelocities will be exchanged.