Question

Answer to the following questions by using the above capacitor combination circuit. The values of capacitors are Ci=18 uF, C2=6 uF C3=36 uF Ca=18 uF and Supply voltage, V=72v a) What is the total charge stored in the equivalent capacitor? (2 mark) PHY2011 Final Exam Fall 19-20 Couse Instructor-Sajeena Harees Page q=0/1-8 t/Rc) = R6 = 10/RC =% 1 1,22

Answer 1

Solution CA - Griven that! (= 18 MF = 18x1067 C2 = 64 F = 6x106F C₂ = 36 M F = 36x1067 (4 = 18 MF - 18x10 F V=72V Equivalent capacitor C&C3 are connected - in parallel, hence the equivalent capacitor of C2 f Cz is given c'= (a + 5. C2 = 64F c = 16+36) 4F Y C3 = 36 ME | c'= 42 M F = 42 X100F @ 7

Now C Now a c' & ca are connected in series. Thus Equivalent capaciter of circuit is given as Ś E Ć t : +++ Heartbeat Tamil 42 MF icipiLII1111111 to to tu 14 + 3 > 126 { c = 126 ME C 7.4147 IM • Thus the How the equivalent capaciter is 7.41 MF total charged stored in Equivalent - capaciter is q = CV

- q = 7.418106 X72 Sr. C = 7.0MF Tv=72V 34F = 16°F 3 9 : 533.52 x 176 C > 19:533.52HC The total charge stored in Equivalent capacitor is 533.52 MC. (6) The Electric potential energy stosed in Equivalent capacitar is given as Ue = 1 Qv Here q = 533.52 MC = $33.52x106c V=72V Ve= I x 33.52x106 x 72 e = $33.524 36 4156 e = 19206.72 x 106 joule e = 1.921 X 102 joule) The energy stored is 1.921 x 10² joull.

C 99 a Licz an V=72V We have 9 533.524€ (MC) 7 q = 533.52 4C qot q = 533.52 MC. » & Across C viza 533.5246 - VI T8 MF - V - 29.64 volt The voltage stored in a 18 29.64 volt Across C₂ & C 7 Both are in parallel same voltage stered. v' = az a

GMF 36 ME (533.5246 - 93) = 23 {-q₂ + q - 533.524 72 = 6X533.52 MC 19 = 457.30 4C MILI டடடடடடட Thus 2 = 533.5246 - 457.3046 19- 76.2240 92 - 9 Now How Now - - (3 457.30 MC 76.224c = 36MF Ğ MF V = V '= 12.7 Volt » Voltage across C2 & 3 is 12.7 volt.

Now Across Car q V4 - CA 533.52 MC V4 - T8MF 3 / V4 = 29.64 volt The voltage stased in (4 is 29.64 volt - Answer Connected ② q = $33.52 MC 6 e = 1.921 x 102 joule © Voltage across a = 29.64 volt 0 G - 12.7 volt 1. C = 12.7 volt CA = 29.64 in parallel )) u