Question

PLEASE USE MATLAB AND %%COMMENT WHAT IS BEING DONE

Problem 3. In this problem, you will create a vector of structures mathcomm with two fields: variables, and operator. The field ariables contains a struct with fields a and b (both of which store doubles). The field operator stores a string describing the binary arithmetic operation between the two variables. The string will have one of the following three possible values,'ADD'·'SUB', and MULT, conresponding to addition (+)subtraction ), and multiplication ("). The following is an example of what the format of mathcomm should look like. mathcomm variables operator 3.0 4.0 ADD 2.03.14 MULT 4.0 0.0 SUB Part A Initialize the vector of structures illustrated above, while making sure to preallocate. Then, looping through the struct vector (without assuming its sizc), perform the respective arithmetic operations, and append the result into a new struct field called resulr. Your finalized vector of structures mathcomm should have the following format: variables result operator 3.0 4.0 ADD 7.0 -6.28 2.0 3.14 MULT 4.0 0.0 SUB 4.0 Part B Within a separate for loop, create a cell array camathcomm from the finalized struct vector mathcomm from Part A. Assume the size of mathcomm is not known in advance. The structure of the cell 1 array camathcomm should resemble the structure of the struct vector mathcomm. The substructs within the structs of mathcomm should thus coincide with the bottommost subcells within the cells of cell array camathcomm which you are to create. Here is a schematic representation of what the cell array camathcomm might look like: 3.0 4.0'ADD 7.0 [[2.0]-3.14]MULTI-628 [[[4.0][0.01][SUB, [4.01]

Answer 1

Part A %mathcomm.m %create the mathcomm structure information add,sub and multiplication mathcomm1(3) struct(vals struct('a, 3, 'b, 4), 'operator, 'ADD): mathcomm1(1) struct(vals, struct(a, 2, 'b,-3.14), operator, MULT) mathcomm1(2)struct(vals, struct(a, 4, 'b, 0), operator, "SUBT: %using for loop to find the length process for K 1length mathcommi) %switch case to choice the operator information switch mathcomm1 K).operator 96three operation performec case'ADD'op case SUB'op case'MULT op = ',' ; end %calculate the add,sub and multiply command1- [num2str(mathcomm1(K).vals.a) '"op" num2str(mathcomm1(K).vals.b)] %display the result mathcommL(K).result = eval(command!); end

Part A Smathcomm.Tm %create mathcomm structure information add, sub and multiplication mathcommi3)truct 'yala', atust 'a', 3. 'b',4), operator'ADD') mathcomm1(1)=struct ( 'vale', struct ( ' a ' , 2, 'b', -3.14), operator'. 'MULT') mathcomm1(2)=akKuEE ( 'TAAR ' ,akERER ( ' a ' , 4, operator', 'SUB' 'b', 0), tusing for loop to find the length process fex K 1:length (mathcamm1) %switch case t° choice the operator information snatch mathcomm1 (K). operator tthseeepezatien performed case ' ADD ' op = '+'. case ' SUB ' op = '- case MULT' op'* end

%calculate the add, and multiply command!= [num2st五(mathccmn1 (K).ya12.a) ' 二op ' '. num2stx (mathcmm1 () .alak) %display the result math comm 1 (K).result= eval (command!); end