There is not any external torque on the system so angular momentum will be conserve.
Linitial = Lfinal
I1wi = (I1 + I2)wf
So in asked terms -
Wf = I1W1/(I1 + I2)
A solid cylindrical disk with moment of inertia I, rotates about a vertical axle through its center with angular ve...
24 4 points Conservation of angular momentum: A disk with moment of inertia I1 = 3kgm rotates about a frictionless, vertical axle with angular speed wi = 8Rad/s. A second disk, this one having moment of inertia 12 = 1kgm and initially not rotating, drops onto the first disk. Because of friction between the surfaces, the two eventually reach the same angular speed W2 . What is w2? 13 Before After 24 Rad/s 12 Rad/s 6 Rad/s 16 Rad/s 4...
A cylinder with moment of inertia I1 rotates with angular velocity ω0 about a frictionless vertical axle. A second cylinder, with moment of inertia I2, initially not rotating, drops onto the first cylinder (Fig. P8.55). Because the surfaces are
rough, the two eventually reach the same angular velocity,ω.Figure P8.55(a) Calculate ω. (Use I1
for I1, I2 for I2, and w0
for ω0 in yourequation.)(b) Show that energy is lost in this situation (Do this on
paper.Your instructor may ask you to turn in this work.), and...
A uniform disk with mass M and radius R is rotating about an axis through its center-of-mass. The axis is perpendicular to the disk. The moment of inertial for the disk with a central axis is I MR2. Two non-rotating smaller disks, each with mass M2 and radius R/4, are glued on the original disk as shown in the figure. (a) Show that the ratio of the moments of inertia is given by I'/I = 35/16, where I' is the moment...
A solid disk rotates in the horizontal plane at an angular velocity of 0.0612 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.134 kg·m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.398 m from the axis. The sand in the ring has a mass of 0.509 kg. After all...
A solid disk rotates in the horizontal plane at an angular velocity of 0.0647 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.199 kg·m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.420 m from the axis. The sand in the ring has a mass of 0.499 kg. After all...
A solid disk rotates in the horizontal plane at an angular velocity of 0.056 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.059 kg·m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance 0.34 m from the axis. The sand in the ring has a mass of 0.54 kg. After all the...
A solid disk rotates in the horizontal plane at an angular velocity of 5.00 × 10-2 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.15 kg.m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg....
A solid disk rotates in the horizontal plane at an angular velocity of 0.038 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.12 kg · m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg....
A disk with moment of inertia 9.15 × 10−3 kg∙m^2 initially rotates about its center at angular velocity 5.32 rad/s. A non-rotating ring with moment of inertia 4.86 × 10−3 kg∙m^2 right above the disk’s center is suddenly dropped onto the disk. Finally, the two objects rotate at the same angular velocity ?? about the same axis. There is no external torque acting on the system during the collision. Please compute the system’s quantities below. 1. Initial angular momentum ??...
please answer 5 and 6
im sorry thats the closest pic i can get to
it
the disk ntating with a constant angular accelerstion Assurse the axle is frictionkess Ca) Calcudlate the magnituke and direction of the net torpsue prodhuced by the twe lorces b) Determine the magnitude of the angular acceleration of the disk rad/s Cakulate the angular momentum, in kg mP/s, of an ice skater spinning at 6.00 rew/s given is moment of inertia is 0 rew/s given...