Question

5. Indicate the mols present in the following solution: a) 0.25 M Baci2 in 1 liter b) 0.25 M C2H5OH in 0.5 liter c) 0.20 M KCI+0.25 M K2CO3 in 0.250 Liter d) 20 ml of 0.20 M HCl + 10.0 ml of 0.500 M HCI 6. Calculate the following quantities: a) milliliters of 0.75 M HCl required to neutralized completely 25.0 ml of 0.15 M Ba(OH)2 b) if 30.0 ml of 0.75 M HCl solution is needed to neutralize a 45 ml solution of Ca(OH)2, what is the concentration of Ca(OH)2 in the solution?

Answer 1

Tay 6.25m Back in 12... we know molarity volume (ish) moles = m x volume ( is a : 0.25 x 2 moles . .0.25 .. by o.asm. ang on molarity. (m) is 0.5 L . moles volunie (int). moles : mx volume (ina) 1 . 2. 0.25% 0.8 moles 0.125

cy 0.2om kell + o.arm to coz is d'art for keen 1 moles: mx (volume is w .. 0.2 x 0.25 = 0.050 moles Fore Kzlaz moles = mx (volume is 2) 20.25 x 0:25 = 0.0625 moles i m hul oiam tel + lome of o.5 of ay dome for first hel solution molesz 0.2 x, 1007 j. 0,004 solution Ror gond nice o 5 x 10 lory moles :ooos moles 0.009 0004 + 0 al
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