Question

9. I xgram= 25.5% Solid magnesium combines with fluorine gas producing solid magnesium fluoride. How much magnesium metal and fluorine gas is required to produce exactly 50.0 grams of the magnesium fluoride product? 12 - 1 xmol Imoll 12

Answer 1

Mg + F2 --------> MgF2

for Mg

according to balanced reaction

62.3 g MgF2 require 24.3 g Mg

50.0 g MgF2 require 50 x 24.3 / 62.3 = 19.5 g Mg

mass of Mg require = 19.5 g

for F2

62.3 g MgF2 require 38 g F2

50.0 g MgF2 require 50.0 x 38 / 62.3 = 30.50 g F2

mass of F2 required = 30.50 g