Question

Consider a classical calculation of the potential energy of a snapshot in time of a classical H2 molecule. The electrons are labeled 1 and 2. The nuclei are labeled A and B. Use the following distances R = 74.0 pm, rA1= 52 pm, rB1=90 pm, rB2=52 pm, rA2= 90 pm, r12= 128 pm. Use Coulomb's Law to calculate the potential energy of this arrangement of particles in kJ/mol. Is the overall potential energy attractive or repulsive for this arrangement?

Answer 1

According to the conlombs low Pored between the two charge partiele of Charge qi e q2 Mespectfully Tata Ins. I un't where you is the distance in Now for moleente Charge of nuelly I fecebasove A land 1. Q despletively in comethits Now for Ho molecule, Charge of the nuellous and electrone are t1600 +10602X.10.19 e cande14602X46-19 seesbeetively ./PB2 Now total potential energy = attractive force of Repulsive farlee

The X 1.602 403 L-1.6021733 f MBL PBL (+lifoni +602X10 + 1.602x70 4466 14 T-1:602876" tito2x70 ,57 X10 4H 52x107 90x12 -96416 ta 52716 2.57 X167 4166 L. Faxo 2 2.54 x 10 -38 2.57 X 10 481 to 12 X 10 1281 -30 2157x10.17X102 x 0.095 --- 362 2 9x109x257810*10** 0109 3-0. 9252 x ia It is a goto

So for a mole t molecule, the total potential energy is, 23 = - O. 9252 x 10 x 6.023X10%3more = -5.57258100 y mole =-5.5725 x 10 kJ/mole As the overall potential energy is negative so overall energy is attractive for this arrangement