2.1) The moles of the gases present are calculated:
n F2 = P * V / R * T = 3 atm * 2.25 L / 0.082 * (120 + 273) K = 0.20 mol
n Cl2 = 5.75 * 4.5 / 0.082 * (120 + 273) = 0.80 mol
The average molar mass of the final gas is calculated:
MM ave = Xi * MMi = (0.2 * 38) + (0.8 * 71) = 64.4 g / mol
2.2) The reaction that occurs is:
2 KClO3 = 2 KCl + 3 O2
It is necessary that the vapor pressure of the water at that temperature is 0.06 atm
The moles of O2 are calculated:
n O2 = (0.95 - 0.06) * 0.25 / 0.082 * (35 + 273) = 0.0088 mol
The mass of KClO3 is calculated:
m KClO3 = 0.0088 mol O2 * (2 mol KClO3 / 3 mol O2) * (122.55 g KClO3 / 1 mol) 0.719 g
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Section 11 (48pts total/&pts per question) partial credit given for work shown, AND work is required for credit...
Describe your solutions in detail, because partial credit will be given based on your work. If additional information is necessary in solving the problems, DO use your engineering sense and provide reasonable assumptions and explanations. You may use your calculator if necessary. Use a language of your choice. Note: The following information may be used. Gas constant, R-8.314 J(mol K)-8.314 kPa L/(mol K)-0.082 L atm/(mol K)-6.132 lbr ft/(gmol K)=1,987 cal/(mol K). Atomic mass of N-14; Atomic mass of O= 1...