Let initial mass = 100 g
final mass = 3.1 g
And n be the number of half life
Initial mass/final mass = [2}^n
100/ 3.1 =[2}^n
Then n=5
option D
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Ag2SO3 ---> 2Ag+ + SO32-
given solubility = 4.6x10^-3 g/L convert this to mols/L,by dividing
with molar mass
4.6x10^-3 g/L/295.80 mols/g = 0.01555 x10^-3 mols/L
Ksp = [Ag}^2{SO32-}
=[ 2*0.01555 x10^-3 mols/L]^2*0.01555 x10^-3 mols/L
= 1.5 x10^-5+-3+-6 = 1.5 x10^-14
Ksp = 1.5 x10^-14
option C
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18)
correct statements are
B) Dynamic equilibrium occurs when rate of forward reaction = rate
of reverse reaction
Only one statement is correct
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16) How many half-lives are required for the concentration of reactant to decrease to 3.1% of its original value? A...
9. What does it mean if Keq < 1, at equilibrium? The concentration of reactants is greater than the concentration of products. b. The concentration of products is greater than the concentration of reactants. The rate of the forward reaction is greater than the rate of the reverse reaction. c. d. The rate of the reverse reaction is greater than the rate of the forward reaction. e. The concentration of products and reactants are about the same. Which of the...
if you could check to see if my answers were correct and help
me solve the one that arent it would be very much apritiated thank
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