The enthalpy change for the reaction of hydrogengas with bromide to produce hydrogen bromide is 68.2kJ for the quation as written
H2(g)+Br2(l)=2HBr(g)
delta H=-68.2kJ
What is the enthalpy change per mole of hydrogen bromide produced

The enthalpy change for the reaction of hydrogengas with bromide to produce hydrogen bromide is 68.2kJ for the quation a...
The rate of disappearance of hydrogen bromide gas in the reaction at 150 oC is 0.190 mol L-1 s-1. 2HBr(g) → H2 (g) + Br2 (g) What is the rate of appearance of hydrogen gas?
Hydrogen bromide will form hydrogen and bromine when heated strongly. 2HBr (g) <-> H2 (g) + Br2 (g) If 0.670 mol HBr is placed in a 3.00 L flask, and K equals 0.01712 at 900 K, what concentrations will the equilibrium mixture be composed of?
The enthalpy change for the following reaction is 81.1 kJ. Using bond energies, estimate the H-Cl bond energy in HCl(g). 2HCl(g) + Br2(g)2HBr(g) + Cl2(g)
Question 5 The spontaneity of a reaction depends both on the enthalpy change, Delta H, and entropy change, Delta S. Reactions that release energy produce more stable products, and the universe tends toward disorder. Thus, an exothermic reaction with a positive entropy change will always be spontaneous. Mathematically, this relationship can be represented as where Delta G is the change in Gibbs free energy and T is the Kelvin temperature. If Delta G is negative, then the reaction is spontaneous....
At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H2 (g) + Br2 (g) 2 HBr (g) A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.546 mol of H2 present. At equilibrium, there are ________ mol of Br2 present in the reaction vessel. Group of answer choices 0.000 0.440 0.546 0.136 0.304
8.66 (a) Use bond enthalpies to estimate the enthalpy change for the reaction of hydrogen with ethene: H2(g) + C2H4(g) right arrow C2H6(g) (b) Calculate the standard enthalpy change for this reaction using heats of formation. Why does this value differ from that calculated in (a)?
A scientist measures the standard enthalpy change for the following reaction to be -87.5 kJ : 2HBr(g) + Cl2(g)2HCl(g) + Br2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(g) is kJ/mol.
The water-gas shift reaction CO(g)+H2O(g)?CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ?H?=?41kJ. Could you increase the equilibrium yield of hydrogen by controlling the pressure of this reaction? If so would high or low pressure favor formation of H2(g)?
A scientist measures the standard enthalpy change for the following reaction to be -79.7 kJ: 2HBr(g) + Cl2(9)—2HCl(g) + Br2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of Br2(g) is kJ/mol. Submit Answer Retry Entire Group 9 more group attempts remaining
A scientist measures the standard enthalpy change for the following reaction to be -77.5 kJ: 2HBr(g) + Cl2(g) 2HCl(g) + Br2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HBr(g) is kJ/mol.