Question

Part A. caculate the molarity.

6.65 g of NaCl in 250. mL of a NaCl solution

Part B. calculate the volume, in liters, for each of the following

34.0 g of NaHCO3 from a 1.00 M NaHCO3 solution

(express your answer as three significant figures)

Part C. calculate the final concentration of each of the following

1. a 20.0 ml sample of an 7.0% (m/v) KBr solution is diluted with water so that the final volume is 222.0 mL

2. a 4.0 mL sample of a 40.0% (m/v) acetic acid (HC2H3O2) solution is added to water to give a final volume of 48 mL

(express your answer as two significant figures)

Answer 1

Soln. Part C-1. Formula used Mass/Volume percent - Mass of socute ey) Volume of Solution (ml) X100% liven- 200 ml sample of 70% (m/w) KBn solution untume solution is 22 2.0 ML - final vowme of so To find final in concentration Initially 2.ome sample of 7% (m/v) KBM solution. mass of KBr (9) x100 75 - 20 . mass of RBr (g) = 1.49 finally : 22210 me volume of solutions. mass of solute = 1:49 mass /vocea percent = x100 222 = 0.63 % (W/V) KB. centration is 0.629 0.63 % (m/v) KRr. final concentration is Hence . .

Part 6.2- Formula used mass of solute (9) mass/volume porcent = X100% volume of solution (me) arven. 4 ml sample of a 40.0% (mn) acetic acid solution. final volume of solution is 40ml. To find. Final concentration. Initially. v solution. ame sample of 40% (miv) acetic acid - mass of acetic acid cg) 40 xico volume of soveticu (ml) mars of acetic acid 40= X100 = mass of acetic acid = 1.6 g - 48 ml. Nolume of solution is mass of select = nog mass/ volume percent = 1 xloo 3.33 % (m/v) acetic acid. so, is 3.33 %(min) The final concentration acenc acid.


Solm bot A Formula vied Moles of solute Molarity - ri Litter of southe Cuiven - 6.65g of Nace in 250 mL of a Nall solution moles of Nace (solute) : Given mals Molar mass 6.65 58.44 0.1138 moes solution = 250 6 = au 0.25 l of Nace sola. 250 ml of Nach tooo Molarity = conto 30.4552M Mocarity of 6.65g of Nall in 250 ml of anach solution is 0.4552 Part B Formella used mases of solute Molarity - lither solution Cuiven. 34.09 NAHCO3 1.00 NaHCO, solution moles of Nahlas = 34 = 0.4048 moles mores of solute = lithes of solution Lithes of sometion = 0,405 L Volume of the solution is 0.4052 you 34g of Nanco in IM NaHCO3. 34 Molan 1= 84 solution