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15.0 L of an ideal gas at 298 K and 3.13 atm are heated to 400 K with a new pressure of 6.00 atm. What is the new volume...

15.0 L of an ideal gas at 298 K and 3.13 atm are heated to 400 K with a new pressure of 6.00 atm. What is the new volume?

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Answer #1

PV=nRT

P= pressure

V= volume

n= no.of moles

R= gas constant

T= temperature

IPv=nRTs Ideal gas equation Ideal are initial V = 1500L T,=298k P = 3.13 atm final V = ? T2 = 4ook P = 6:00 atm 2 = ( x ) x T

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15.0 L of an ideal gas at 298 K and 3.13 atm are heated to 400 K with a new pressure of 6.00 atm. What is the new volume...
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