Question

A 45.0 ml solution of 0.0400 M hydroxylamine is extracted with 125 mL of solvent. The partition coefficient for the reaction is 5.00 and the pK, of the protonated form of hydroxylamine is 5.960. Calculate the concentration of hydroxylamine remaining in the aqueous phase at pH = 4.50 and pH = 6,50. [hydroxylamine) at pH = 4.50: M [hydroxylamine) at pH = 6.50: M

Answer 1

Hydroxyl Solute amine is is weak Parnition base (weak hase) ir hase coefforent, Koe [Bona D2 Borg (Bongo torut Co wat vattoo r Calcurate [Bha+[BftJaq. Distribution KoCOH C Buton Blan [BHtaa 2 lbox [Baa Сои Substitute above equation in Blitan DZ CBD og (Baat 14x(Blaa Coran EBorg 2012 2 ko ot loa Corzet ko. pla & pin a 14.000 2 kg 14.0oo-5-960 top 6.so - 168-04 I de Calculations & on por 214.000 pou 2 14-00 -6.50 27.50 =) con 2107.50 D 25.00 16750 CTO-Too-040

D2 3-88 Toral mole of B in arphase 2 a onoomx450ML 1-80 mmoles ler a moles of hydroxyl amine exhached to organic phase then ammoles D2 – 125 ml 1-80mmoles - x 45-om CB) in organic) [B) in aqueous- 8.88 [1.80-x) 2 x x 45 =) x (in immoles 252.8801-807 (3-88 + u 3-88 2 1.647 mmoles ~ 1.65 mmoles aq phase moles in 2 o.15 mmole CB2 in 0-15 mmoles in aq-phase 45-omi after exhachon. 20.00 33m. Cat PH25.50)

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