Question

The PV diagram below represents 3.21 mol of an ideal monatomic gas. The gas is initially at point A. The paths AD and BC represent isothermal changes. If the system is brought to point C along the path ABC, find the following: Р, atm 4.0 1.0 200 VL 4.01 (a) the initial and final temperatures of the gas initial 60.9 final 75.9 (b) the work done by the gas kJ (c) the heat absorbed by the gas kJ

Answer 1

of moles initial lemperature of gas, erparaune Pa VA= Oues Given 3 21 no. Peirt A, fune at nRTA Kvow, we P VA TA = inA 3.21 R=0.082 atmL mol k VA 4.01L Pa= 4x4-0) 60-9 K TA .21 K0-082) 60.9k TA final lemperatme of gas, te lewperatune P Ve at Point c R=0082 h 3-2 Tc ne R P= 1atm IX20 75-98K 1 O.082 x3.2) 75.98 K 1 for Curue Pa Va P VD AD VD16.04L Ix VD 4 x 4.01 done wevk wok done ABC- wurk done aleug Ec a lng work dene ABCE work dlene AB + wrk done wrk dene alory RCU8-) Aら 16.0 4 L

4 otm x( 16.04 4.0) L doug AB 2 Loork, done 48 12- atm L u.875 ヒj BC n RT lu/2 work done T75-98 K O.082 amk, mol k n= 3.21 mol, 16.04 h V 20 L , 20 BC 3-21 X0.0 82 K 75.98 n alany 17 4428 atmL 0.447 F -322 行 total uork deue alag 4.875 t0.447 2 ABC EC PE (Ve-VE) work done ( 20-4.01 IS 99 amL L .62. i work, done 3-7019 i 5.322 - い62 2 3- To19 Ej wark, done heat absortaed fr cyclic froces, buow we 3-7019 Kj heat absetbed by gas