Question

6. The legal definition of intoxication in some states is a blood alcohol (C2H5OH) level of 0.1% (by mass) or higher. A given analysis requires 48.02 ml of 0.05182 M K2C1207 to titrate a 48.91 g sample of blood Assume only C2H50H reacts with K2Cr207 to produce Cr' (aq), CO2 (g), and H20 (1). Was the person this blood was taken from legally intoxicated?

Answer 1

Mass of blood sample = 48.91 g

Molar mass of Ethyl alcohol = 46 g/mol

As per the balanced chemical equation 1 equivalent of ethanol is equal to 1 equivalent of potassium dichromate.

The report shows exceeding the given intoxication limit. The blood sample collected was

CH5OHK,C,0CO 24L+21 2Co,+ 3H, O + eguatn As per lu blance d ehanu mole ap ethanol 's 0idicd by Imele of 1 used 48.02ml X 0 65M Number af mole of, iouo 0.00 2U && wwch cimplies melu aHsH blood Baurple heame number af 0 048 oyidined Ahich t's are 0 G024 8mela f omolesy Mobn N = 000248x 463/m MA SS 71 Mass %ethanel in Moed 11 t448 loa 48.91 3 O.234%