Question
Find the chemical structure using the wave spectrum shown
Problem I1.3 40 Exact M.S. (E)- 84.0575 UVAmax-209 (E-16,000) 328 (E-50) FT-IR (NEAT) 20 3000 2000 WAVENUMBERS (CM) 1800 1200
0 0
Add a comment Improve this question Transcribed image text
Answer #1

13C NMR spectrum shows 5 peaks. Therefore, there are at least 5 carbon atoms in the compound.

The total integration value of 1H NMR spectrum adds up to = (3 + 2 + 1 + 1 + 1) = 8. Therefore, there are 8 hydrogen atoms in the molecule.

The doublet at ~9.2 ppm in 1H NMR spectrum and the peak at ~191 ppm in 13C NMR spectrum indicates the presence of an aldehyde group in the molecule.

Hence, the molecular formula of the compound = C5H8O

Exact mass, m/z = 84.06 (matches with the EI exact mass given)

Degree of unsaturation = (2C + 2 - H)/2

                                      = (2 x 5 + 2 - 8)/2

                                      = 2

IR spectrum peak assignment:

ww 40 C-H symmetric & anti-symmetric alkyl 20 FT-IR (NEAT) C-C stretch C-H stretches stretches C=O stretch 4000 1200 2000 M00

13C NMR peak assignment:

D T B 13C NMR 62.3 MHz COCI CH3 E .C D B H2 192 191 190 CDCI 09 a 0 0 40 30 20 130 120 110 100 180 170 150 140 10 0 pem

1H NMR peak assignment:

250 Jantaulalnd 10 Ha/dv. E 250 MHz CDCI 4.2 Hz/mm 1H NMR 250 MHz CDCI 5.9 Hz/mm 3H H Llulul 9.0 8.4 8.2 7.0 8.6 6.0 E C 2H B

High intensity (\epsilon = 16000) peak at mar = 209 nm indicates the T T transition in UV spectrum.

Low intensity (\epsilon = 50) peak at mar = 328 nm indicates the n T transition in UV spectrum.

Hence, the chemical structure that satisfies the given spectral data:

media%2Ffcf%2Ffcf267f4-2d5b-41f8-92b0-d5

Add a comment
Know the answer?
Add Answer to:
Find the chemical structure using the wave spectrum shown Problem I1.3 40 Exact M.S. (E)- 84.0575 UVAmax-209 (E-16,0...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Use the following wave spectrum to identify the chemical structure Problem 11.10 60 40 Exact M.S. (CI) 129.1279 FT-...

    Use the following wave spectrum to identify the chemical structure Problem 11.10 60 40 Exact M.S. (CI) 129.1279 FT-IR (NEAT) 20 UVAmax BLANK 4000 3000 2000 800 WAVENUMBERS (CM) 1200 1000 100. Mass Spec. CI 70eV 60 55 40 43 129 20 40 60 70 80 100 110 120 40 m/s 13C NMR 62.3 MHz COCI CDCI luuluuluu 50 40 30 20 10 120 S00 70 130 160 150 140 170 H 500 MHz 3H CDCla 5.2 Hz/mm H 10H...

  • Find the chemical structure using the wave spectrum shown Problem 11.4 100 40 40 Exact M.9. (EI)-98.0732 FT-IR (NEAT...

    Find the chemical structure using the wave spectrum shown Problem 11.4 100 40 40 Exact M.9. (EI)-98.0732 FT-IR (NEAT) 20 UVAmaxBLANK 4000 300 2000 WAVENUMBERS (C) s000 s00 100 42 Mass Spea. El 70eV 60 40 20 150 70 105 45 so m/z 13C NMR 62.3 MHz COCls ywwA 224 222 220 218 216 214 212 COCI uwwlu 20 120 60 30 0 ppm 160 130 110 100 90 80 50 40 10 180 170 150 140 3H 1H NMR...

  • Find the compounds using IR and NMR: Problem 25 2251 IR Spectrum (liquid film) 800 1600...

    Find the compounds using IR and NMR: Problem 25 2251 IR Spectrum (liquid film) 800 1600 1200 4000 3000 2000 v (cm) 100 Mass Spectrum M 117 80 77 60 91 40 20 CgH7N 200 80 120 160 240 280 40 m/e expansion 13C NMR Spectrum (100.0 MHz, CDCI, solution) 130 129 ppm DEPT CH Cн,! сн! expansion 130 129 ppm solvent proton decoupled (ppm) 40 200 160 120 80 H NMR Spectrum (400 MHz. CDCI, solution) TMS 10 7...

  • Find the compounds using NMR and IR: Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000...

    Find the compounds using NMR and IR: Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000 v (cm) 800 3000 1200 4000 100 Mass Spectrum 73 140 138 80 No significant UV 60 115 absorption above 220 nm 40 M 194/196 (1% ) 20 CeH1102Br 120 160 200 240 280 40 80 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH, Cн, сн! solvent proton decoupled 8 (ppm) 160 120 40 200 80 H NMR Spectrum (200 MHz, CDCI,...

  • What is the molecular structure? 2 4 CHAPTER 8 ASSIGNED PROBLEMS Problem 8.43A MASS I 20...

    What is the molecular structure? 2 4 CHAPTER 8 ASSIGNED PROBLEMS Problem 8.43A MASS I 20 sen par 43 100 131 85 109 95 1827 ? 185 50 200 50 100 150 200 m/z IR 100 90 E 70 4000 3000 2000 1000 Wavenumber (cm-1) 'H NMR 600 MHz 1260 1240 Hz 780 760 740 Hz 4.5 4.0 3.5 3.0 2.5 2.0 1.5 Ppm 1C/DEPT NMR 150.9 MHz 170 160 150 140 130 120 110 100 90 80 70 60...

  • Identify the structure using H NMR, C13 NMR, IR spectrum, and Mass Spectroscopy. The data is...

    Identify the structure using H NMR, C13 NMR, IR spectrum, and Mass Spectroscopy. The data is given below: PLEASE SHOW WORK! Problem #4: 'H NMR: ppm 8.318 Hz 4159 4151 4059 4051 3041 Height 11.86 12.01 11.46 11.38 5.28 8.118 8.104 6.081 CH CH 0.97 1.00 1.06 å7 65 Ppm C5H₃ Oz 13C NMR: 5 carbons ppm 168 151 140 124 130 180 160 140 120 100 .80 ppm f IR: TRANSMETTANCE e-H Spa D-H C-O1 C-C 02 15.00 HAVENUMERI...

  • Can somone show me how to do the 1st problem? Need to find the LS and...

    Can somone show me how to do the 1st problem? Need to find the LS and SS for the fit and the LH and SH for the hole. Fits are all SHAFT BASIS METRIC but the shaft and hole diameters can not be used right out of the table. This is because the 3mm shaft tolerance does not match. You will need to lookup the "Fit" from the table, and then use the LS (Largest Shaft) and SS (Smallest Shaft)...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT