Question

Calculate the osomolarity of 0.5 g/mL of magnesium sulfate heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol

Calculate the osmolarity of 1 Liter of solution that contains 40mEq of sodium, 20 mEq of potassium, 60 mEq of chlorine and 5% w/v of dextrose (mol way: 180 non-electrolyte).

My teacher gave me the answer but I didn't understand how they got it. thank you.

2. Calculate the osmolarity of 0.5 g/mL of magnesium sulfate heptahydrate - MgSOa.7H20 MW-246.47 g/mol 0.59 Calculate the osmolarity of 1 L of solution that contains 40 mEq of sodium, 20 mEq of potassium, 60 mEq of chloride Answer: 4057 mOsm/liter c-0020 mol woo 3. and 5 % w/v of dextrose (mol wt: 180 non-electrolyte). Is the solution isotonic, hypotonic or hypertonic to plasma (290-300 mOsm/L)

Answer 1

IML X1000 become 0.5g = 0.59x1000 = 500g = 500g mil 1000ml = soog xfa male al = 2.02864 melle [246.479* converting from a to mal Now, in of solute Mgsdy .7H20 solution Masou.7. H2O dissociates inta Mgat, son and 7H2O molecules. Ho molecules being part of the solvent Ho and are not counted as solute particles as solute particles are particles different from solvent Then IMA SOq-tң,o su kа ko AoLia particles (1 Mgat, 150%). So, osmolarity iu 2.02864 und 2 osonol = 4:0573 osund = 4057.3 mosmal û T4057 osmol/ 3 1000mL (IL) has dextrose = 5% w of 1000mL 5 x 1000g = 50g x/ mat) = 0.278 mal . converting g of dextrose to make of dextrose destrose Now, osmdarity = number of males of solute particles 2 per L of solution = (40x10² + 20x10% Prox103 10.278) osmol = = 397.8 mlm Seitse . Thus, solution is hypestonic. nia یه ل مه با ) 00

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