Question

A 18.7-g sample of ice at -13.1°C is mixed with 118.5 g of water at 80.0°C. Calculate the final temperature of the mixtu...

A 18.7-g sample of ice at -13.1°C is mixed with 118.5 g of water at 80.0°C. Calculate the final temperature of the mixture, assuming no heat loss to the surroundings. The heat capacities of H2O(s) and H2O(l) are 2.03 and 4.18 J/g∙°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

page:01 Answers According to the given information, to calculate the final tempenature. Given, the mass of the ice given a 18page:02 The heat released when Heb(d) at 808 es converted into Hoole) at oc = 118.5g (u. 18 Jlg91809 ? 39686.45 £ 39.696 KJ .

Add a comment
Know the answer?
Add Answer to:
A 18.7-g sample of ice at -13.1°C is mixed with 118.5 g of water at 80.0°C. Calculate the final temperature of the mixtu...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • [References) A 18.0-g sample of ice at -13.6°C is mixed with 105.1 g of water at 80.0°C. Calculate the final temperatur...

    [References) A 18.0-g sample of ice at -13.6°C is mixed with 105.1 g of water at 80.0°C. Calculate the final temperature of the mixture, assuming no heat loss to the surroundings. The heat capacities of H2O(8) and H2O(l) are 2.03 J/g.°C and 4.18 J/g.°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol. Temperature = ГС Submit Answer Try Another Version 5 Item attempts remaining

  • A 20.8-g sample of ice at −14.1°C  is mixed with 112.9 g of water at 77.3°C. Calculate...

    A 20.8-g sample of ice at −14.1°C  is mixed with 112.9 g of water at 77.3°C. Calculate the final temperature of the mixture assuming no heat loss to the surroundings. The heat capacities of H2O(s) and H2O(l) are 2.03 and 4.18 J/g·°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol.

  • ا ما حال ده اند A 13.6-g sample of ice at -14.8°C is mixed with 101.5...

    ا ما حال ده اند A 13.6-g sample of ice at -14.8°C is mixed with 101.5 g of water at 80.0°C. Calculate the final temperature of the mixture, assuming no heat loss to the surroundings. The heat capacities of H2O(s) and H2O(1) are 2.03 and 4.18 J/g.°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol. Final temperature = °C

  • step by step solution please A 24.0-g sample of ice at –12.1°C is mixed with 104.2...

    step by step solution please A 24.0-g sample of ice at –12.1°C is mixed with 104.2 g of water at 80.0°C. Calculate the final temperature of the mixture, assuming no heat loss to the surroundings. The heat capacities of  and  are 2.03 J/g⋅°C and 4.18 J/g⋅°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol. Temperature = ? °C

  • Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C,...

    Given that the specific heat capacities of ice and steam are 2.06 J/g°C and 2.03 J/g°C, the molar heats of fusion and vaporization for water are 6.02 kJ/mol and 40.6 kJ/mol, respectively, and the specific heat capacity of water is 4.18 J/g°C, calculate the total quantity of heat evolved when 24.1 g of steam at 158°C is condensed, cooled, and frozen to ice at -50.°C.

  • 9. Four ice cubes exactly at-50 °C with a total mass of 53.5 g are combined with 1 15 g of water at 75 °C in an insulated container. If no heat is lost to the surroundings, what is the final tempe...

    9. Four ice cubes exactly at-50 °C with a total mass of 53.5 g are combined with 1 15 g of water at 75 °C in an insulated container. If no heat is lost to the surroundings, what is the final temperature of the mixture? The heat capacity of ice is 2.03 JIg C and that of water is 4.18 JIg C. The heat of fusion of water is +6.01 kJ/mol. (1.5 pts) 9. Four ice cubes exactly at-50 °C...

  • Two 20.0 g ice cubes at −14.0 ∘C are placed into 235 g of water at...

    Two 20.0 g ice cubes at −14.0 ∘C are placed into 235 g of water at 25.0 ∘C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of H2O(s) 37.7 J/(mol⋅K) heat capacity of H2O(l) 75.3 J/(mol⋅K) enthalpy of fusion of H2O. 6.01 kJ/mol

  • Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at...

    Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T, of the water after all the ice melts. heat capacity of H2O(s) heat capacity of H2O(1) enthalpy of fusion of H,O 37.7 J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol Ti =

  • You have a block of ice at a temperature of -100°C. This block of ice is...

    You have a block of ice at a temperature of -100°C. This block of ice is made from 180g H2O. The block of ice will be heated continually until it becomes super-heated steam at a temperature of 200°C Cice = 2.03 J/g-K ΔHfus=6.01 kJ/mol Cwater = 4.18 J/g-K Csteam = 1.84 J/g-K ΔHvap=40.67 kJ/mol What is the enthalpy change raising the temperature of 180 g of ice at −100 °C to 0°C? What is the enthalpy change upon melting 180...

  • Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at...

    Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of H2O(s) heat capacity of H2O(1) enthalpy of fusion of H20 37.7 J/(molK) 75.3 J/(mol·K) 6.01 kJ/mol Tf= 9.96

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT