How many mol of solid LiA would have to be added to 1.0 Lof a 4.064 M HA solution in order to obtain a buffer of 3....

Question

Question

science chemistry

Answer 1

Answer #1

Ka = 4.44*10^-6

pKa = - log (Ka)

= - log(4.44*10^-6)

= 5.353

use formula for buffer

pH = pKa + log ([LiA]/[HA])

3.08 = 5.3526 + log ([LiA]/[HA])

log ([LiA]/[HA]) = -2.2726

[LiA]/4.064 = 0.0053

[LiA] = 0.0217

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 2.169*10^-2*1

= 2.169*10^-2 mol

Answer: 2.17*10^-2 mol

Answer 2

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