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The following reaction is a single-step, bimolecular reaction: CH, Br+ NaOH → CH,OH+ NaBr When the concentrations of CH3Br an
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C143 BN + Naon CH3OH + Na Bos Rate of nen R, - * [ 0113 BM] [Nand] -7 0.0030 - K ***.125 0.125 0.0030 = 0.95 K y concentratieEqua но я (: (б), вое яе 1 Pz_ 7.8.125810-3k 0.0030 0.25k · 3 9.375 105 a. Rate of Rxn = 9.375 x 10-5 Mils) Concentration 07

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