Question

U ul HU poruwuyu m oguce de ce Male 15,604 26,807 Female 25,071 12,979 14537959 17,797 18,165 18,955 15,425 12,463 16,877 13,679 25,217 16,681 17,946 Ho: Mo = 0 word(s) H:Hd < 0 word(s) (Type integers or decimals. Do not round.) Identify the test statistic. t= -0.44 (Round to two decimal places as needed.) Identify the P-value P-value = 0.337 (Round to three decimal places as needed.). What is the conclusion based on the hypothesis test? Since the P-value is greater than the significance level, fail to reject the null hypothesis. There is no speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature conclusion reached in part (a)? The confidence interval is a word(s)< d < 0 word(s). (Round to the nearest integer as needed.) Enter your answer in the edit fields and then click Check Answer

Answer 1

solution Here Hold = 0 as he ldco from the given data n=8 d=-1610 sd = 10265 . -1610 Test statutic t= ds = 10268/58 = Co.nu dif=n-1=8-1=1, P-value = [0-335 since the P-value greater than a, so we fail to reject the null hypothers At asy. confidence tape 2.365 The 95%.c-I for d is I Itaja ( 3 ) = -1610 + 2-365 (1026) =-161048220.77669830-196,6670 796) 1os 8583.12 = (-10193-12, 6973-12)