Question

The answers are in red. I just want to know how to correctly solve this...

A hotel claims that 85% of its customers are very satisfied with its service. Complete parts a through d below based on a random sample of five customers. a. What is the probability that exactly four customers are very satisfied? 0.3915 (Round to four decimal places as needed.) b. What is the probability that more than four customers are very satisfied? 0.4437 (Round to four decimal places as needed.) c. What is the probability that less than three customers are very satisfied? 0.0266 (Round to four decimal places as needed.) d. Suppose that of five customers selected, two responded that they are very satisfied. What conclusions can be drawn about the sample? The probability that 2 out of 5 customers are very satisfied is 0.0244, assuming that 85% of customers are very satisfied. Therefore, it is not likely that randomly selecting 5 customers would result in 2 responding that they are very satisfied. (Round to four decimal places as needed.)

Answer 1

- Ans: P = 0.85, n = 5 w xn Bm (n=5, P=0.85) P (x = 4) - 5 (0.85)" (0.15) = 10.3915] 6 p (x34) = P(x-5) = 5 (0.85 (0.150 = (0.4437) c) p (23) = P(x=0) + p (x = 1) +8 (x =2) = 0.0266) d) P(x=2) - 5 (0.85) 2 (0.15)3 = 0.0244 the probability that 2 out of 5 customers are very satisfied as (0.0244)