Question

A reaction that is second order in one reactant has a rate coefficient of 0.05 dmmols1. If the initial concentration of the r

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer

secand ader eacion nty rated Pata law is रवि lahere LA1 A1 9nitise Canentratia nactamt Canent ratian eactant thme t Rate 1 Ld

Add a comment
Know the answer?
Add Answer to:
A reaction that is second order in one reactant has a rate coefficient of 0.05 dmmols1. If the initial concentration of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The rate coefficient for a chemical reaction is 4.4 x 10-351 If the initial reactant concentration...

    The rate coefficient for a chemical reaction is 4.4 x 10-351 If the initial reactant concentration is 0.9 mol dm, what will the concentration (in mol dm) be after 60 seconds? Express your answer in mol dm, correct to three decimal places. Please do not include the correct units (mol dm) in your answer.

  • A second order reaction where the starting reactant concentration is 0.0963 M has a measured rate...

    A second order reaction where the starting reactant concentration is 0.0963 M has a measured rate constant of 0.70 M/s at 10 oC. What is the concentration of the reactant after 36.0 seconds? - report your answer in three significant figures - do not write your answer in scientific notation - do not include units

  • The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...

    The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt[A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02[A]02 for [A][A] and rearrange the equation to: t1/2=0.693k t1/2=0.693k This equation calculates the...

  • The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...

    The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...

  • A reaction was determined to be second order with respect to a reactant with a rate...

    A reaction was determined to be second order with respect to a reactant with a rate constant of 0.695L/mol*s at 300°C. If the initial concentration is 0.0455 M, what is the concentration after 365 seconds?

  • Referen The initial concentration of the reactant in a first-order reaction A → products is 0.528...

    Referen The initial concentration of the reactant in a first-order reaction A → products is 0.528 mol/L and the half-life is 27.0 s. (a) Calculate the concentration of the reactant (in mol/L) 54.0 s after initiation of the reaction. moll (b) How long (in s) would it take for the concentration of the reactant to drop to one eighth its initial value? (e) How long (ins) would it take for the concentration of the reactant to drop to 0.0330 mol/L?...

  • The integrated rate law allow chemists to predict the reactant concentration after a certain amount of...

    The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...

  • The reactant concentration In a second order reaction was 0.340 M After 280 seconds and 3.80×10^-2...

    The reactant concentration In a second order reaction was 0.340 M After 280 seconds and 3.80×10^-2 M after 850 s. what is the rate constant for this reaction? Part D The reactant concentration in a second-order reaction was 0.340 M after 280 s and 3.80x10-2 M after 850 s. What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash....

  • 1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reacti...

    1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 2. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 3. The rate constant...

  • Part B What was the initial reactant concentration for the reaction described in Part A? Express...

    Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Part C The reactant concentration in a first-order reaction was 6.60×10−2M after 20.0 s and 5.50×10−3M after 70.0 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary,...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT