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26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and the system
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Answer #1

ICE Table:

[Co] [Br2] [COBr2] initial 0.5 0.4 change -1x - 1x +1x equilibrium 0.5-1x 0.4-1x +1x

Given at equilibrium,

[COBr2] = 0.233

+1x = 0.233

x = 0.233

Equilibrium constant expression is

Kc = [COBr2]/[CO][Br2]

Kc = (+1x)/(0.5-1x)(0.4-1x)

Kc = (+1*0.233)/(0.5-1*0.233)(0.4-1*0.233)

Kc = 5.23

Answer: A

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