Question

A block of mass 3 kg goes down at a velocity 3.73 over an inclinated plane with an angle of 40º when it is at a distance of 1m of a spring with a constant of 251N/m. the coefficient of kinetic friction betweeen the block and all of the surface is 0.2. calculate the maximum compression of the spring .

Answer 1

m N VO m = kq Vo = 3.73 m/s 0 - 40° K = 251 N/m MR = 0.2 da im fp = fricksborforu = Mig N N= Normal foru free body diagram of block L ysino N = my coso I = 3x9.81 x Cos 40* ong coso? = 22.545 Newton mg sino - f = ma a> acceleration. masino - MN = ma 3x9.81 x sin 48 -0.2x22.545 = 3x a Ta = 4.8 m/ 27 Initial velouty 7 Block = Vo = 3.73) Quelvation = a: 4.8 m/2 distance travelled = d = 1 m ge2 = x² +said . .. 3-732 + 2x 4.8* 1 Tv = 23.52 myl y this is the Velocity of block right before Scanned with hitting the spring. anada CamScanner

block will werke mail at Paximum con forentino al Serisy all the kinetic Enesey associated with be converted to spring Enugy. * £ mv² = 1kx² H: V 23.51 st a = 2.57