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6. You prepare two solutions in the lab. One contains 0,010 M HNO in DI water. The other contains 0.010 M HNO3 and 0.040 M KN
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Answer #1

The pH will be almost the same.

Only 0.01 M HNO3: pH = -Log[H+] = -Log(0.01) = 2

Mixture of 0.01 M HNO3 and 0.04 M KNO3 in water: pH = 2

Explanaiton: KNO3 salt is neutral, which contributes [H+] = 10-7 M

i.e. [H+]total= (0.01 + 10-7) M

i.e. pH = -Log(0.01 + 10-7) ~~ 2

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