Question

Worksheet 8 (Intro) 8. A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases the tank are 35 atm of O, 5.0 atm of N2, and 25 atm of He, what is the total pressure inside of the tank? 9. The partial pressure of oxygen gas in a mixture of oxygen and nitrogen gases is 1.02 atm. The total pressure of the mixture is 2.43 atm. Calculate the partial pressure of nitrogen gas. 10. Voyager 7 has obtained the composition of the atmosphere of Titan, Saturn's largest moon. The total pressure is 1220 mm Hg and the atmosphere consists of 82 % N2, 12 % Ar and 6.0 % CH. What is the partial pressure of each gas? 11. The highest pressure ever produced in a lab was about 2.0 x 10 atm. If we have a 1.0 x 10 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be?

Answer 1

Solection: 8. Partial Pressure of ony gen; Po2 = 35 atm. Partial Pressure of helium; PHe=25 atm Partian Pressure of Nitrogen, PN2 = 5 atm : Total Pressure inside the tank va Protex = Poz+ Pue & Prize = (35+ 25 +5 atm = 65 atm brosa si g. Partion Pressure of oxygen Po2 = 1.02 atm. Partian Pressure of Nitrogen; PH2 = ? Total Pressure of the mixture; P Total = 2.43 atm. . Ptotal = Poz + PN2 - TN2 = Ptotal - Pos os - Cent are grot wit in I) IT = (2143-1.02) atm - 1:41 atm.

10. Totene Pressine; Protal = 1220 mmHg. The atmosphene Consists of 82% N2; 12% An and 6 to Chy. :. Partion Pressure of nitrogen, PN2 = 82 2 +6 x 1220 mmity rob b ios X1224 mmHq = 1000-4 mmHg parition Pressure of Angon; Pan = Partion Pressure of methan, Petty = 12 x 1220 mmHg 146.4 mmHg 0 & 1228 mmitg - 73.2 mmHg Dich . According to the ideal gas equation. PV=RRT. or, Piv, = P2 v ₂ (NR,T constant ). 106 alm o ond tothonte a) V2 = P, (Initicul Pressure) = 2x106 alme no V (Initial volume) = 1.0x10-5 liter of this cool P2 (Final Pressure) = 0.275 atm . V₂ (final volume) (2 x 106 )* (1.0 x10-5) - 72.727 liter. 0.275 at 12. According to ideal gas equation. - PV=NRT w (Pine Constant) Po v (Initian volume) = 2.31 Ti (Initial tempera tene) = 2088 25°c = (273+ 25) =298k V2 (Final volume) = 400L T2 (final temperature) = ?

298 2:3 = 57826.087 k = 5155 3.087c. .: The balloon was hot 5.1558104oc. 13. According to ideal gas equation PV=nRT. et entret) v W ych PinR Constend vi (Initial volume) = 2:00 Ti (Inition temperature) = (25+273) = 298k. V2 (final volume) =? Tz (final temperatine) = -4°C = (273-4) = 269k V2 = √ 1 x T2 or, z = 21 22 x 269 = 1805L. .. New volume of the bottle = 1.805 liter or mit wel a 14. Acconding to the ideal gas equation - priboroso PV=nRT (vn, R Constant Pi (Inition Pressure) - 36 Psi Til Inition tempera tence) = (273+40) = 313k. Jos P2 (Final Pressure) = 1 Tz (final tempera tene) = 298k. a P2 = 1/xT2 - X 298 = 34.275 Psi "The tine lost a significant amount of Pressine 34.275 Psi.

15. According to ideal gas equation- PV = nRT. Pivi - Pak (n, R Constant) Pi (Initial Pressure ) = 365 mmitg. " Initar volume) = ? Ti (Inital temperature ) = 325k. P2 (final Pressure) = 1.2 atm*760 = 912 mming V₂ ( final volume) = 4,8 x 103 m. and Tal final temperature) = 320k goot. . V = P2 V2 x II 912x4.8x103 325 320 x 365 soopt = 1.22x109 m2. - 12.2L the inition volume of the gas is 12.2 liters. 16. According to ideen gas equation. More Pv=nRT " PN = P2 V 22 (9, R Constant) pa npr) = 2 atm. P V=28 litens T, = 318k. q = 34 liters ders T2 = 308k. . Px28 318 P2 x 34 - 308 a hay = 1.254 ", P = Possy ; . P - Plasy a zatim ", 0.254 P, = 2x1.254 atm n, P, = 9.874 alm. : The oniginal Pressine of the gas =9.874 atm.

According to ideal gas equation - PV = nRT or 2, T1 = M2 Tz (Pv, R Constant). 2 = 0. 27 mol n2 = ? T =(22+273) = 295k. T2 = (150 * 273) = 423k. no niti m2 = - 0.27 x 295. = 423 = 0.1883 mor. the remain Ny in the jon 0.1883 mol = 0.1883428 Ž 5.272 gm. According to ideal gas equation- PV=MRT. 1 2 3 4 5 (P. V, R Conshin) 2.00 gm Helium - 1 mole Helium . n,= 1 n = ? =21 V₂ = 2.7L m2 = V2 x 2 = 2.7* Ž = 1:35 mole : 1:35 mole Helium z 1:35*2 = 2.7 gm of helium. .. (2-7-2) = 0.7 gm of helium was added to the cylinder. 19. o) As a Piston Compresses ain in cylinder, the gas Pressine żncreases. 6) As a ballon Cools in a freezer, its volume decreases. 9 As can drives on a highway, the fire Pressure decreases.