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For the reaction below 2 PC13 (9) + 0,09) = 2POCI; (g) 1) ZVOITZU BAI-T209 AH°: -508.3 kJ/mol AS = -178.3 /mol K o rongo a) C
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The reaction 2 paz (3) +0,() 2 poetz (1) given ah = -508.3 kJ mell as = - 178.37 milk! AG = 4H-TAS Teampunature 25° x 298k =AG = 4Gº + RT in (P pouz) ppelz) Poz] As the reaction is at equilibrium AG=0 AG=RT ln (PPouz)? B (PPU3) ² (P02] =-2.303 RT do

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For the reaction below 2 PC13 (9) + 0,09) = 2POCI; (g) 1) ZVOITZU BAI-T209 AH°: -508.3 kJ/mol AS = -178.3 /mol K o...
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