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| This pressure is |
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The concept used to solve this problem is variation of pressure with depth in a fluid.
First use relation of atmospheric pressure and static fluid pressure to calculate the total pressure
Finally use the relation between total pressure and area to calculate the force.
If a fluid is within a container then the depth of an object placed in that fluid can be measured.
Expression for the weight of the object is,

Here, W is the weight of the object, m is the mass of the object and g is the acceleration due to gravity.
Volume of the object is,

Here, A is the area of the object and h is the depth of fluid.
Expression for the force is,

Here, F is the force.
Expression for the static fluid pressure is,

Here,
is the static fluid pressure.
If the container is open to the atmosphere above, the atmospheric pressure must be added to get the total pressure.
Expression for the total pressure is,

Here,
is the total pressure and
is the atmospheric pressure.
(1)
Expression for the total pressure is,

Here,
is the total pressure at
below the surface of the ocean.
Substitute
for
and
for
.

Expression for the force is,

Here, F is the force.
Substitute
for
and
for A.

(2)
Expression for the static fluid pressure is,

Consider the pressure at 20 m below the surface of the ocean. Since, the pressure at 20 m surface will be pressure at 10 m surface plus the pressure of the 10 m surface below the top 10 m surface.
Thus, this pressure must be equal to that at a depth of
plus the weight of a column of seawater
in cross section and
high.
The weight of a column of seawater
in cross section and
high plus the weight of a column of air with the same cross section extending up to the top of the atmosphere is about
.
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