Question

TKANDIENT STA BILTY avesTi 5ay mnte bus thegh doukle lpaialle) Grat A Sachenau machine transhemes wt a Cennectedd to reactana t o.1 pu emd hansmissun Line th o,45 pu readana hr Cah ciuit jory jo,1 Loar t the mahme rabg AU en reactana 6 Setumine the variahn f the dlectricel pe teanaleralle S Assume V= ,0 pu ad the mhinik bu Cieuit of the tmisbin in oblam hrlatomahip been the tranbmite dectncad ane 6. Assume tha ofhe variable t Gkateh theVanatim af PV 6 th Conditims ly is awailakle, ct emam undanged md the (n) f th syatom in ) 1.1 ps Tfarent for of 2 Ciruits m Serice Cen tL Jhe mle & unde shadyc ellom Hhe atsge Eomd the Sute 6ource Condition av sketeh the peed angle Curves r the Candh tions

Answer 1

Sal i) jo. 45 +00 jo-1 jo.45 NOw Suppose Vs Aud (Xay equivalent reactance X-g=Co.1540.1)+ Lo.ts110.+s) 0. 25 + 0-45 S 0-95 0. 475 2. 2 jo.15 Xeg ltencs electrical pouer trans feralle ( Le. Xeq 1X ns-2.1 Sins 0.475 2 2.1 8in S p Now, if only available 1-e transmission ine is So Xey will change 11 Ome 2 0.1541o.1+0.9s b.7 P

So. trans mited ele ctrieal pouwer CP 67 1-4-28 Sh 8 pu Neus Con ditions for rated An tais case an valtge f bus NsIKatV here -Ipu Vs-1201j013 jo 1 1-22 L34.99 1-22 L34.9 J 1.428 p 2.1 pu

t e vz A Ppanend power NI- 1-1 Po gnenS I 1.1 pv V 1 And, j0-475pu veltage 1-1 2-Car-6joc V, エメeg ナ &ourte Here, given 0-&S gnpaie facter is 89 I- 1.1 L-Ces-10 E - (1.1X 0. 475)90- CA0-85 1L0 0.5225 s2 21 1L0 2 1.35 L 19.2 Henes 1-35 pu メ & 19.2 Pouir tranauteol (f Xeg aren opparant Pomer= t. V 1.1 gun& O-475 = 2.315 &ins

Hanee, 2-315 p CA