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1. Let ab and f E C[a, b], and let E(0, ))- - (co +c)w(a) da for some weight function w(x) >0. (a) Use calculus to write down

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Answer #1

a) E(Co, C) [f(x) (coc1)] w(x) da

Then f(x)-(coc12 w(x) da = 0 a E(co, ci) acO aco means

a E(co, c1) 2 aco f(x) (coC1)] w(x) dr = 0 and

-E(co, e) 2 [f (x) (coc1ax)] w (x) dar 0

So that w() da f (x)w(x) da w(x) dr ci co a eb a a rb cb rf (x)w(x) da 2w(x) dx rw(r) drci CO is the required system

b) The theorem is not known to me so I cannot comment if its the same set of equations or not

c) w(x)1, f(x) &,a = 0, b = 1 we get

w() da f (x)w(x) da w(x) dr ci co a eb a a rb cb rf (x)w(x) da 2w(x) dx rw(r) drci CO equals

dx x da 1 dr + c co dx dr drc CO

So that

CO +

Solving this, we get b 1 6 CO

Meaning the required approximation to f(x)a is 6

Graph of the two function is given below for reference:

1 f(x)2{0x<1} 2 x01 _ 6 (1x50 3 0:5 0.5 0 LC X +

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