Question

5. 0/1 points SerCP11 8.A.P.076. The figure below shows a whers being used to run out of her board. A force of magnitude 10 N orted her only as shown (Assume that the force the hammerets on the natis parallel to the nail and perpendicular to the position vector from the point of contact. The component of this force's ever arm is som.) Single point (a) Find the force exerted by the hammer claws on the nail (Enter the magnitude) (1) Find the force exerted by the surface at the point of contact with the hammer head. (Assume the positive is to the right) direction counterclockwise from the Submit Answe

Answer 1

As shown in the enclosed drawing -

Vertical force component on nail = 140 × 30/5 = 840 N. (moments)

Horizontal force component on nail = 840 * tanθ

= 840 * tan30 = 485 N

(a) Total force exerted by the hammer claws on the nail = √[840² + 485²]

= 970 N (Answer)

(b) Horizontal component of force = 485 - 140 = 345 N (balance of horizontal force components)

Vertical component = 840 N (balance of vertical force components)

Therefore, the force exerted by the surface at the point of contact with the hammer head,

F = 345i + 840j assuming x is positive to the right and y is positive upwards.

So, magnitude of force, |F| = sqrt[345^2 + 840^2]

= 908.1 N

Direction, $\Theta$ = tan^-1(840 / 345) = 67.7 deg. in counter clockwise direction from + x-axis.