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2. (70pt) For the system shown below: w bending moment (M) and shear force diagrams (V) using Moment Distribution (Cross) or
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4OKHIM uokN 5M -31 fixed end moments : anhèloctasle-> -ve clockurise tve. uR6-66 kH-m r-h iya - hーでJい + u26.66 kM-M MES-20 MPkn-m 31 3 T slope defiectim egyctins: My- -u26.66 t 2x 3 EI -4-26 .66 + 6 EI@2 426.66 + 0-2S EL Ma-y- 6 EI + u26-66 + G26-66Mg- 82 2x28 2a2 + 0. G.403 _E1g ¢ 0-625o, E1 Mt-2 - <xREI [90, + @, G 4 - 6250z E1 O. 180 t RE1 QO, 4 ©3 180 +2x 4E1 더 E10, += -^ + 5- یو 83 ما ح ع 50 0.6 + ج 830 + و ۰ue3C*و5816-* 6 0= e1G 0۰695 v6-66 # و0۰۹1a ۸ لباتذ و .: E3G ۴°٠6 5e1 G ـععادعـــــ7 E1 O1こ 36-29 E 1 3= -12.09 1 u.9E1 02 o 6250, E1L :-426-66 0.62 5D,E1.+ y.334 @,8L: t007 E1 O1こ 36-29 E 1 3= -12.09 1 u.9E1 02 o 6250, E1L :-426-66 0.62 5D,E1.+ y.334 @,8L: t00T 1 36.29 T2 -91.7 T3 -12.0967 -495.435 kN-m M 4-2 289.11 kN-m M 2-4 220.08 kN-m M2-5 -110.04 kN-m M 5-2 -69.0188 kN-m M 2-1sa. o33 u9s.u35 237-11 BM due to exteanal 2 220.08 16.bu

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