A 65.0mL aliquot of a 1.30M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is dilute...
A 65.0mL aliquot of a 1.30M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 173 mL of water. What is the final concentration? Assume the volumes are additive.
Homework Answers
By dilution law,
M1V1 = M2V2
1.30×65.0 = 208×M2
M2 = 0.406 M
In 2nd case
M2V3 = M3V4
0.406 × 104 = M3×(173+104)
M3 = 0.153 M
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