Question

4. What is the limiting reactant, theoretical yield, and % yield of iron metal (in kg) if 76.0 kg of Fe2O3 reacts with 22.1 kg of carbon to produce 42.3 kg Fe according to the following reaction: 2Fe2O3(s) + 3C(s) 4Fe(s) + 3CO2(g) Limiting Reactant - Fezoz Mass of Fe₂O₂ = 760kg Mole of Fe₂O₃ =475 grud Mass of carbon 22.1kg Mole of carbon = 1841.7 mol Theor. Yield =53.12 kg % Yield = 79.7%

Answer 1

Answer + 2Fx 036) - 76.0kg 360 - 4f 5) + 36 (9) mas 22.1kg 42.3kg Molar mais 159.699/mo) 12.018/ moi 55.858)moj Available moles of fez oz = 76.0 X 10% = 475.92 mol 159.69 g/mol Augilable moles of C = 22.1X109 g - 12.01 g/mol = 1840.13 mo) 2 mole fello reacts with 3 mol so 475.92 mol Fezo will reach with 2 x 415.92 mol = 713.88 mol C available moles of C qre more than moles of Crequired means C is excess reactant s Feroz is limiting reactant Limiting reactant : Fes] Theoretical Yield of Feng reacted te when all of limiting reactant moles of Fe produced Fe₂O₂ reacted holes of

moles of e produced = 2x urs.92 mol = 951.84 mois mass of fe produced = moles of fex molar mass of pe = 951.84 mol X 55.85 9. Imoll : 53160. De 6 9 = 53.16 kq 6 kg 1. Theoretical yield of Pe = 53.16 kg % Yield = actual giedd X100 theoretical yield 42.3 kq vioo . 53.16.kq y Yiely = 79.57 y.