Question

Suppose two children are using a uniform seesaw that is 3.00 m long and has its center of mass over the pivot. The first...

Suppose two children are using a uniform seesaw that is 3.00 m long and has its center of mass over the pivot. The first child has a mass of 30.0 kg and sits 1.40 m from the pivot. (a) Calculate where the second 18.0 kg child must sit to balance the seesaw.

(b) What is unreasonable about the result?

(c) Which premise is unreasonable, or which premises are inconsistent?

Please show work and explanations.

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Answer #1

Thet=0 30 x 1.40 = 18 x x b) . 30x1-40 ) 2.33m 18 1.40+4 = 3m but 2-33+1.45 378 M23 The distance is beyond the seesaw length

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