Extend Linked List in C
// Exercise 5
/* Parameter head points to the first node in a linked list, or
is
* NULL if the list is empty.
*
* Parameter other points to the first node in a linked list, or
is
* NULL if the list is empty.
*
* Extend the linked list pointed to by head so that it
contains
* copies of the values stored in the linked list pointed to by
other.
*
* The function terminates (via assert) if the the linked list
* pointed to by head is empty.
*/
void extend(node_t *head, node_t *other)
{
}
I need to call the push function
node_t *push(node_t *head, int data)
{
node_t *newnode = malloc(sizeof(node_t));
assert(newnode != NULL);
newnode->data = data;
newnode->next = head;
return newnode;
}
void extend(node_t *head, node_t *other)
{
node_t *temp=head;
//moving upto end of the list1
while(temp->next!=NULL)
temp=temp->next;
//now for every element in other creating its
copy
while(other!=NULL)
{
node_t *n = new node_t();//creating
new node
n->data=other->data;//copying
its data
temp->next=n;
temp=temp->next;
other=other->next;
}
}
Extend Linked List in C // Exercise 5 /* Parameter head points to the first node in a linked list, or is * NULL if the l...
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Answer all questions
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This is a code for linked list,
it is about adding a node in the middle of a list, I am really
confused why int i = 2? can't it be 0?
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