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(Data source: Applied Linear Statistical Models, 5th Ed., by Kutner, Nachtsheim, Neter, and Li, McGraw-Hill, 2005) An of...

(Data source: Applied Linear Statistical Models, 5th Ed., by Kutner, Nachtsheim, Neter, and Li, McGraw-Hill, 2005)

An office equipment corporation performs preventive maintenance and repair on the line of copiers that it sells. For 45 recent service calls data has been collected on the number of copiers serviced during the call and the number of minutes spent on the call by the service person. The company would like to develop a regression model that can be used to predict the amount of time (in minutes) that a call will require based on the number of copiers that need to be serviced.

(1) The first service call scheduled for tomorrow involves servicing 5 copiers. Predict, with a .95 level of confidence, the time that will be required for this service call. Note that you need to use a PI, not a point predictor. Please explain the thought process behind your work.

(2) Repeat (a) but now assume that the call involves servicing 13 copiers rather than 5 copiers. Please explain the thought process behind your work.

(3) What key assumption is made when doing the prediction requested in (2) that is not necessary for the prediction requested in (1)? Please explain the thought process behind this. Why is solving for 5 copiers different than solving for 13 copiers?

Date below

Minutes Serviced
20 2
60 4
46 3
41 2
12 1
137 10
68 5
89 5
4 1
32 2
144 9
156 10
93 6
36 3
72 4
100 8
105 7
131 8
127 10
57 4
66 5
101 7
109 7
74 5
134 9
112 7
18 2
73 5
111 7
96 6
123 8
90 5
20 2
28 2
3 1
57 4
86 5
132 9
112 7
27 1
131 9
34 2
27 2
61 4
77 5
0 0
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Answer #1

Answer:

() The R command to find the prediction interval is: newdata<-data. frame (Serviced-5) > predict (Model, newdata, interval=p

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