Question

Calculate the percent yield if 30.4 grams of C ₄H ₈Br ₂ are produced when 10.0 grams of C ₄H ₈ are reacted with excess Br ₂. The reaction is C ₄H ₈  + Br ₂ ---> C ₄H ₈Br ₂

Answer 1

he bromination reaction, САНs + Вт, - АНs Вт, As per the above reaction, Imol of Ca Hg reacts with excess Brg to give Imol of CA Hg Brq 2 olar mass of Calgi :::= (4x atomie wt: of Carbon)+ (8x atomie pt. of Hydrogen) = (4x12) + (8x1 gmail = 56 g moro - Molar mass of Carg Bry = (4x atomic wt. of carbon) + (8xatomie wt. of Hydrogen) + (2x atomic wt. of Bromine) = (4x12) + (8x1) = (2x 79.9) gmail = 215.8 g moi! Note - here atomic wt. of the elements were taken in a gmoi unit. atomic wit. of carbon = 12 gmoi :.. ::" in of Hydrogen at gmor' . :» :of Bro mine = 79.9 g may * Therefore, inol o Cq Hg = 56 g of Cq Hg reacts with excess Bra to give imot of Calg Bra = 215.8 g of Calg Brig

: 56g of Cats Ig » ?? 109 » » produces 215.8 g of Carg Br2. ? 215.8 D moi 56 215.8x10 g of Cq Hq Bra = 38.5 g of CG Hg Bra .. . Theoretically 38.5.g of earig Bra is produced . from log of eqHg. Again, Experimentally, .30.4 ġ of Ca Hq Bry were produced from tog of eats ... 2. Percent yield of the Bromination reaction Experimentally obtained Pdt. Weight x 100% * Theoreitically obtained Pdt weight = 30.49 38.57 X100% = 178.96.4. 794% pereent yield of the Bromination is 79%