a) Mass of sucrose = moles×molar mass
= 0.075×342 (molar mass of sucrose = 342 g/mol)
= 25.65 g
b) Molarity = moles×1000/volume (in ml)
= 0.075×1000/150
= 0.5 M
Please give feedback!
show work The Mole (1.5 pt) If you plan to dissolve 0.075 moles of sucrose (C12H2011) to make 150 mL of solution (a)...
If you plan to dissolve 0.075 moles of sucrose (C12H22011) to make 150 mL of solution... (a) How many grams of sucrose should you plan to measure out? (b) What is the molarity of the resulting solution?
show me the work in a clear hand writing so i can understand
please.
The Mole (1.5 pt) If you plan to dissolve 0.075 moles of sucrose (C12H22011) to make 150 mL of solution... > (a) How many grams of sucrose should you plan to measure out? (b) What is the molarity of the resulting solution?
If you dissolve 412 mg sucrose (formula weight: 342.29 g/mol) in 60 mL of water: a. What is the concentration of sucrose in mM in µM? b. If you take 5 mL of this solution and dilute it to 250 mL, what is the concentration of the glucose in the resulting solution in µM? c. How many nano moles of sucrose are present in 10 mL of the diluted solution?
If you dissolve 412 mg sucrose (formula weight: 342.29 g/mol) in 60 mL of water: a. What is the concentration of sucrose in mM in µM? b. If you take 5 mL of this solution and dilute it to 250 mL, what is the concentration of the glucose in the resulting solution in µM? c. How many nano moles of sucrose are present in 10 mL of the diluted solution?
When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when thinking about stoichiometry. However, when we dissolve a solid (also known as a solute) in a solvent to form a solution, the solute becomes evenly distributed throughout the solution and we need to know how many moles of solute are present in a particular volume of solution. pt. 1 A solution is created by dissolving 10.0 grams of ammonium chloride in...
How many grams of magnesium cyanide are needed to... make a 275 mL of a 0.075 M solution? add to 275 mL of water to make a 0.075 molal solution? Please show work and explain
Just answer part 2 and 3 please
(0.3 point) Part 1 ii See Periodic TableSee Hint A solution is created by dissolving 12.5 grams of ammonium chloride in enough water to make 355 mL of solution. How many moles of ammonium chloride are present in the resulting solution? moles of NH4CI 0.233 When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when thinking about stoichiometry. However, when we dissolve a solid...
21. A student correctly determines that 17.1 grams of sucrose are needed to make 50 mL of a 1 M sucrose solution. When making this solution in lab, the student measured 50 mL of water and massed 17.1 grams of sucrose. The student then mixed the two together into a new beaker. The student's resulting solution was not 1 M sucrose as intended. After the student mixed sucrose and water, the resulting solution was poured into a graduated cylinder and...
The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. How many grams of sucrose are needed to make 795 mL of a 40.0% (w/v) sucrose solution? sucrose MISS Use the quantities to show how each calculation is made. Answer Bank Lof solution ml of solution grams of wolute moles of solute % (m/v) = Calculate the molarity of the two...
When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when thinking about stoichiometry. However, when we dissolve a solid (also known as a solute) in a solvent to form a solution, the solute becomes evenly distributed throughout the solution and we need to know how many moles of solute are present in a particular volume of solution. Pt1:A solution is created by dissolving 13.0 grams of ammonium chloride in enough water...