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A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of
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Answer #1

From Continuity equation

A1V1 = A2V2

(pi*d12/4)*V1 = (pi*d22/4)*V2

Given d2=0.769d1

d12*1.47 =(0.769d1)2*V2

V2=2.4858 m/s

From Bernoulli's equation

P1+(1/2)pV12+pgh1 = P2+(1/2)pV22+pgh2

since P1=P2=Patm

=>(1/2)(1000)(1.47)2+1000*9.8*h =(1/2)(1000)(2.4858)2

h = 0.205 m = 20.5 cm

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