Question

52

7.63 7.64 7.65 52 Underwater pressure increases by 14.7 psi for every 10 m of depth. Standing on a boat in scuba gear, you fill a balloon with helium. a. If you take the balloon with you as you dive to a depth of 40 m, what, if anything, will happen to the size of the balloon (assume temperature stays the same)? b. If the balloon slips out of your hand and floats upward before you dive, what, if anything, will happen to the size of the balloon (assume temperature stays the same)? c. If the balloon had a volume of 2 L at a depth of 40 m, what was the original volume of the balloon if we assume the pressure at the surface of the water is 14.7 psi? 3 The lowest recorded atmospheric pressure occurred dur- ing a typhoon in the Pacific Ocean in 1979 and measured 652 mmHg. The highest atmospheric pressure on record occurred in Mongolia in 2001 and measured 814 mmHg. If a balloon were inflated with air to a volume of 10.L under the conditions in Mongolia and then rapidly trans- ported to the conditions described for the typhoon 7.6

Answer 1

Er Susfout of water According to Boyle's low, At constant 'T, an inexease in the P” on a gas will Gesult in a decreas of its volume and vici - VY8Q Pi-1+7 fu Pi Vi = P + Vf| P = initial Presun Vi = initial volume B = final prout Vf = final volume P4 = 73.5 MM for every 10 m, the underwater Pumpura in crecesce by 14.7 Buis Thus, at a depth of 40m, the fresurd increases is given by, 4x14.7 + 14.7 = 73.5 Bxi 46M P.V @ Pi = 14.7 Besi -> Surifas proberce V = livi 73.5 Pivi = Pf Vf V = ? Af = 73.5 fai VH = ? V+= 14-7X Vi 4 = Thus, size of balloon contracts (reduces) to 1 th of its original volume the size again become vi at surface. So, volume becoms 5 times of volume at 40m. Thus, Valoma/size increases". Pi Vi = Pf Vf Vj = PVA Pi = 14.7 PM Vi = ? Pf= 73.5 fri V2L Vj = 73.5 X 2 14-7 Vi = 10L Thus, if the pressure at the surface of water was 147 fri, then the original valury of the balloon was lol.