Given the following electrolytic cell:

The current is discharged into the electrolytic cell containing the solution CuSO4(aq) 1.0M at 25 oC. During the operation of the cell, copper Cu(s) is deposited on one electrode and oxygen O2(g) gas is released, near the second electrode.
O2(g) + 4H3O+(aq) +
4e-
6H2O(l) Eo= 1.23V
Cu2+(aq) + 2e- Cu(s)
Eo= 0.34V
A. The current in the cell is 1.5 amperes. The current is
streamed in 40 minutes.
i. Calculate the mass of copper in grams that have sunk. Show
calculations.
ii. What is the volume in liters of oxygen gas released on 25
oC under pressure of 1.16 atm. Show calculations.
B. Methane gas reacts with chlorine gas according to the reaction given below:
CH4(g) + 2Cl2(g) → CH2Cl2(g) + 2HCl(g)
The following mechanism is proposed for the reaction (all substances in the gaseous state):
Step 1: Cl2 ⇄ 2Cl equilibrium is fast
Step 2: CH4 + Cl → CH3 + HCl Slow step
Step 3: CH3 + Cl2 → CH3Cl + Cl
Quick step
Step 4: CH3Cl + Cl → CH2Cl2 + H
Quick step
Step 5: H + Cl → HCl Quick step
i. Does CH3Cl function as a catalyst or as an
intermediate in the proposed mechanism? Explain.
ii. What is the order of response to Cl2(g) and CH4(g) according to the proposed mechanism? Explain.
Thanks!



Given the following electrolytic cell: The current is discharged into the electrolytic cell containing the solution CuS...
Given the following electrolytic cell:
The current is discharged into the electrolytic cell containing
the solution CuSO4(aq) 1.0M at 25 oC. During
the operation of the cell, copper Cu(s) is deposited on
one electrode and oxygen O2(g) gas is released, near the
second electrode.
O2(g) + 4H3O+(aq) +
4e-
6H2O(l) Eo= 1.23V
Cu2+(aq) + 2e- Cu(s)
Eo= 0.34V
A. Write the direction of the flow of electrons in the
cell.
B. Write the electrolysis equation that occurs in the cell....
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Mg2 ] = 0.774 M and [Sn2 ] = 0.0190 M. Standard reduction potentials can be found here. Reduction Half-Reaction Standard Potential Ered° (V) F2(g) + 2e– → 2F–(aq) +2.87 O3(g) + 2H3O+(aq) + 2e– → O2(g) + 3H2O(l) +2.076 Co3+(aq) + e– → Co2+(aq) +1.92 H2O2(aq) + 2H3O+(aq) + 2e– → 2H2O(l) +1.776 N2O(g) + 2H3O+(aq) + 2e– → N2(g) + 3H2O(l) +1.766 Ce4+(aq) + e– → Ce3+(aq)...
need help for half cell potentials pls calculate step by step
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