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Problem 12-13 (algorithmic) Question Help A potential project has an initial capital investment of $85,000. Net annual revenu

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Answer #1

Initial Capital investment is $ 85,000 (Column 1)

Net Revenue increases @ 6.76% (Column 2)

Discounted revenue @ MARR 16% (Column 3) Calculated as

Revenuex 1.16

PW(N) is cumulative net outcome of the project up to the year (Column 4)

Probability of useful life of the project is p(N) (Column 5)

Summation of PW(N) X p(N) is E(PW) (Column 6)

Variance of Present Worth is

V(PW) = E(PW)? - E(PW)

and Standard Deviation of Present worth is

SD(PW) = V(PW)

Year Cost Revenue Discounted Revenue @ 16% PW(N) p(N) PW(N)*p(N) PW(N)^2 p(N)*PW(N)^2
0 $ 85,000.00 $                  (85,000.00)
1 $ 40,000.00 $                    34,482.76 $                  (50,517.24) 0.02 $ (1,010.34) $ 2,55,19,91,676.58 $          5,10,39,833.53
2 $ 42,704.00 $                    31,736.03 $                  (18,781.21) 0.12 $ (2,253.75) $      35,27,33,955.81 $          4,23,28,074.70
3 $ 45,590.79 $                    29,208.09 $                    10,426.88 0.34 $    3,545.14 $      10,87,19,761.28 $          3,69,64,718.83
4 $ 48,672.73 $                    26,881.51 $                    37,308.39 0.22 $    8,207.85 $ 1,39,19,16,051.05 $        30,62,21,531.23
5 $ 51,963.00 $                    24,740.26 $                    62,048.65 0.18 $ 11,168.76 $ 3,85,00,35,437.95 $        69,30,06,378.83
6 $ 55,475.70 $                    22,769.57 $                    84,818.23 0.12 $ 10,178.19 $ 7,19,41,31,554.37 $        86,32,95,786.52
E(PW) $ 29,835.84 E[(PW)^2] $    1,99,28,56,323.65
V(PW) $    1,10,26,79,053.21
SD(PW) $                    33,206.61
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