Question

Part 6 Calculate (OH) for the strong base solution formed by mixing 14.0 mL of 1.50 10-2 M Ba(OH), with 48.0 mL of 7.6*10-3 M NaOH Express your answer using two significant figures O AEC OD? [OH-] = Submit Previous Answers Request Answer * Incorrect; Try Again; 5 attempts remaining

incorrect answers:

0.0112M

Answer 1

Concentration of mixture = (n1*C1*V1+ n2*C2*V2) / (V1+V2)

where C1 --> Concentration of 1 component

V1-->volume of 1 component

C2 --> Concentration of other component

V2-->volume of other component

n1 --> number of particle from 1 molecule of 1st component

n1 = 2 as 1 Ba(OH)2 has 2 OH-

n2 --> number of particle from 1 molecule of 2nd component

n2 = 1 as 1 NaOH has 1 OH-

use:

C = (n1*C1*V1+ n2*C2*V2) / (V1+V2)

C = (2*0.015*14+1*0.0076*48)/(14+48)

C = 0.0127 M

Answer: 0.013 M